The graph of y=f(x) is given in Figure 12. (x might represent time and y might represent the distance of the bob of a pendulum from its at-rest position. Negative values of y would indicate that the bob is to the left of its at-rest position; positive values of y would mean that the bob is to the right of its at-rest position.)
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Solution (a) Since the point (0,4) is on the graph of f, the y-coordinate 4 is the value of f at 0; that is, f(0)=4. Similarly, when x=3π2, then y=0, so f(3π2)=0, and when x=3π, then y=−4, so f(3π)=−4.
(b) The points on the graph of f have x-coordinates between 0 and 4π inclusive. The domain of f is {x|0≤x≤4π} or the closed interval [0,4π].
(c) Every point on the graph of f has a y-coordinate between −4 and 4 inclusive. The range of f is {y|−4≤y≤4} or the closed interval [−4,4].
(d) The intercepts of the graph of f are (0,4), (π2,0), (3π2,0), (5π2,0), and (7π2,0).
(e) Draw the graph of the line y=2 on the same set of coordinate axes as the graph of f. The line intersects the graph of f four times.
(f) Find points on the graph of f for which y=f(x)=−4; there are two such points: (π,−4) and (3π,−4). So f(x)=−4 when x=π and when x=3π.
(g) f(x)>0 when the y-coordinate of a point (x,y) on the graph of f is positive. This occurs when x is in the set [0,π2)∪(3π2,5π2)∪(7π2,4π].