(a) loga(x√x2+1)=logax+loga√x2+1loga(uv)=logau+logav=logax+loga(x2+1)1/2=logax+12loga(x2+1)logaur=rlogau
A-11
(b)
(c) logax+loga9+loga(x2+1)−loga5=loga(9x)+loga(x2+1)−loga5=loga[9x(x2+1)]−loga5=loga[9x(x2+1)5]