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EXAMPLE 10Using Properties (3), (4), and (5) of Logarithms

(a) loga(xx2+1)=logax+logax2+1loga(uv)=logau+logav=logax+loga(x2+1)1/2=logax+12loga(x2+1)logaur=rlogau

A-11

(b)

(c) logax+loga9+loga(x2+1)loga5=loga(9x)+loga(x2+1)loga5=loga[9x(x2+1)]loga5=loga[9x(x2+1)5]