Figure

The pattern on the left suggests the $n{\rm th}$ term of the sequence on the right.

Pattern	$n$ th	Sequence
$e, \dfrac{e^{2}}{2}, \dfrac{e^{3}}{3}, \dfrac{e^{4}}{4},\ldots$	$a_{n}=\dfrac{e^{n}}{n}$	$\{ a_{n}\} =\left\{ \dfrac{e^{n}}{n}\right\}$
$1,~\dfrac{1}{3},~\dfrac{1}{9},~\dfrac{1}{27},\ldots$	$b_{n}=\dfrac{1}{3^{n-1}}$	$\{ b_{n}\} =\left\{ \dfrac{1}{3^{n-1}}\right\}$
$1,~3,~5,~7,\ldots$	$c_{n}=2n-1$	$\{ c_{n}\} = \{2n-1\}$
$1,~4,~9,~16,~25,\ldots$	$d_{n}=n^{2}$	$\{ d_{n}\} = \{n^{2}\}$
$1,~{-}\dfrac{1}{2},~\dfrac{1}{3},~{-}\dfrac{1}{4},~\dfrac{1}{5},\ldots$	$e_{n}= ( -1) ^{n+1}\left( \dfrac{1}{n}\right)$	$\{ e_{n}\} =\left\{( -1) ^{n+1}\left( \dfrac{1}{n}\right) \right\}$