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EXAMPLE 2Finding a Vertical Asymptote

Find any vertical asymptote(s) of the graph of f(x)=x(x3)2.

Solution The domain of f is {x|x3}. Since 3 is the only number for which the denominator of f equals zero, we construct Table 13 and investigate the one-sided limits of f as x approaches 3. Table 13 suggests that lim

So, x=3 is a vertical asymptote of the graph of f.

Figure 52 f(x)=\dfrac{x}{(x-3)^2}
TABLE 13
\underrightarrow{x~\hbox{approaches 3 from the left}} \underleftarrow{x~\hbox{approaches 3 from the right}}
x 2.9 2.99 2.999 \ \rightarrow 3 \leftarrow 3.001 3.01 3.1
f( x) =\dfrac{x}{(x-3)^{2}} 290 29{,}900 2{,}999{,}000 f(x) becomes unbounded 3{,}001{,}000 30{,}100 310

120

Figure 52 shows the graph of f( x) =\dfrac{x}{( x-3)^{2}} and its vertical asymptote.