Investigate lim using a table of numbers.
Solution We create Table 1 by evaluating f(x) =2x+5 at values of x near 2, choosing numbers x slightly less than 2 and numbers x slightly greater than 2.
\underrightarrow{\hbox{numbers \(x\) slightly less than 2}} | \underleftarrow{\hbox{numbers \(x\) slightly greater than 2}} | ||||||||||
---|---|---|---|---|---|---|---|---|---|---|---|
x | 1.99 | 1.999 | 1.9999 | 1.99999 | \rightarrow | 2 | \leftarrow | 2.00001 | 2.0001 | 2.001 | 2.01 |
f(x) =2x+5 | 8.98 | 8.998 | 8.9998 | 8.99998 | f(x) approaches 9 | 9.00002 | 9.0002 | 9.002 | 9.02 |
Table 1 suggests that the value of f(x)=2x+5 can be made “as close as we please” to 9 by choosing x “sufficiently close” to 2. This suggests that \lim\limits_{x\rightarrow 2}( 2x+5) =9.