Using the Trapezoidal Rule with Empirical Data
A \(140\)-foot \(({\rm ft})\) tree trunk is cut into 20-ft logs. The diameter of each cross-sectional cut is measured and its area \(A\) recorded in the table below. (\(x\) is the distance in feet of the cut from the top of the trunk.)
\(x({\rm ft})\) | \(0\) | \(20\) | \(40\) | \(60\) | \(80\) | \(100\) | \(120\) | \(140\) |
\(A({\rm ft^{2}})\) | \(120\) | \(124\) | \(128\) | \(130\) | \(132\) | \(136\) | \(144\) | \( 158\) |
Find the approximate volume of the tree trunk.
Solution The volume of the tree trunk is \(V=\int_{0}^{140}A ( x) \,dx\), where \(A( x)\) is the area of a slice at \(x.\) Since only eight data points are given, the function \(A( x)\) is not explicitly known. To approximate the volume, we partition the interval \([ 0,140]\) into seven subintervals, each of width \( \Delta x=\dfrac{140}{7}=20\). This partition corresponds to the given data. Using the Trapezoidal Rule, the approximate volume of the tree trunk is \[ \begin{eqnarray*} V= \int_{0}^{140}A( x) \,dx\approx \dfrac{1}{2}(20) \,[ A(0)+2\,A\,(20)&+&2\,A(40)+2\,A (60) +2\,A(80) \\[5pt] &+& 2\,A (100) +2\,A(120) +A\,(140)] \end{eqnarray*} \] \[ \begin{eqnarray*} V &\approx & 10\,[120+2(124)+2(128)+2(130)+2(132)+2(136)+2(144)+158]\\[5pt] &=& 18{,}660 \end{eqnarray*} \]
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The volume of the tree trunk is approximately \(18{,}660{\rm ft^{3}}.\)