Use a Table of Integrals to find ∫dx√(4x−x2)3.
Solution Look through the headings in the Table of Integrals until you locate Integrals Containing √2ax−x2. Continue in the subsection until you find a form that closely resembles the integrand given. You should find Integral 82: ∫dx(2ax−x2)3/2=x−aa2√2ax−x2+C This is the integral we seek with a=2. So, ∫dx√(4x−x2)3=x−24√4x−x2+C