Find \(\int x^{2}( 2x^{3}-4) ^{5}dx\).
The output is \[ \int x^{2}( 2x^{3}-4) ^{5}dx=32\left( \dfrac{x^{18}}{18}-\dfrac{ 2x^{15}}{3}+\dfrac{10x^{12}}{3}-\dfrac{80x^{9}}{9}+\dfrac{40x^{6}}{3}-\dfrac{ 32x^{3}}{3}\right) +C \]
Using Mathematica returns the same result without the constant \(C\).