Find $\int x^{2}( 2x^{3}-4) ^{5}dx$.

Solution Using WolframAlpha to find the integral, input $$\hbox{integrate }x^{\wedge }2((2x^{\wedge }3 ) -4)^{\wedge }5$$

The output is $$\int x^{2}( 2x^{3}-4) ^{5}dx=32\left( \dfrac{x^{18}}{18}-\dfrac{ 2x^{15}}{3}+\dfrac{10x^{12}}{3}-\dfrac{80x^{9}}{9}+\dfrac{40x^{6}}{3}-\dfrac{ 32x^{3}}{3}\right) +C$$

Using Mathematica returns the same result without the constant $C$.