Determine whether the series ∞∑k=1ak= ∞∑k=12kk2+1 converges or diverges.
Solution The function f(x)=2xx2+1 is continuous, positive, and decreasing since f′(x)≤0 for all numbers x≥1, and ak=f(k) for all positive integers k. Using the Integral Test, we find ∫∞12xx2+1dx:lim
Since the improper integral diverges, the series \sum\limits_{k=1}^{\infty}\dfrac{2k}{k^{2}+1} also diverges.