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Concepts and Vocabulary
The series representation of a function f given by the power series f(x)=f(c)+f′(c)(x−c)+f′′(c)(x−c)22!+⋯+ f(n)(c)(x−c)nn!+⋯ is called a(n)______________ ______________ about c.
Taylor series
If c=0 in the Taylor expansion of a function f, then the expansion is called a(n) ______________ expansion.
Maclaurin
Skill Building
In Problems 3–14, assuming each function can be represented by a power series, find the Maclaurin expansion of each function.
f(x)=ln(1−x)
f(x)=−∞∑k=1xkk
f(x)=ln(1+x)
f(x)=11−x
f(x)=∞∑k=0xk
f(x)=11−3x
f(x)=1(1+x)2
f(x)=∞∑k=0(−1)k(k+1)xk
f(x)=(1+x)−3
f(x)=11+x2
f(x)=∞∑k=0(−1)kx2k
f(x)=11+2x3
f(x)=e3x
f(x)=∞∑k=0xk3kk!
f(x)=ex/2
f(x)=sin(πx)
f(x)=∞∑k=0(−1)kπ2k+1x2k+1(2k+1)!
f(x)=cos(2x)
In Problems 15–22, assuming each function can be represented by a power series, find the Taylor expansion of each function about the given number c.
f(x)=ex;c=1
f(x)=∞∑k=0e(x−1)kk!
f(x)=e2x;c=−1
f(x)=lnx;c=1
f(x)=∞∑k=1(−1)k+1(x−1)kk
f(x)=√x;c=1
f(x)=1x;c=1
f(x)=∞∑k=0(−1)k(x−1)k
f(x)=1√x;c=4
f(x)=sinx;c=π6
f(x)=∞∑k=0sin(16(π+3kπ))(x−π6)kk!
f(x)=cosx;c=−π2
In Problems 23–26, assuming each function can be represented by a power series, find the Taylor expansion of each function about the given number c. Comment on the result.
f(x)=3x3+2x2+5x−6;c=0
f(x)=−6+5x+2x2+3x3
f(x)=4x4−2x3−x;c=0
f(x)=3x3+2x2+5x−6;c=1
f(x)=4+18(x−1)+11(x−1)2+3(x−1)3
f(x)=4x4−2x3+x;c=1
In Problems 27 and 28, find the Maclaurin expansion for each function.
f(x)=sinhx
f(x)=∞∑k=0x2k+1(2k+1)!
f(x)=e−x2
In Problems 29–32, use properties of power series to find the first five nonzero terms of the Maclaurin expansion.
f(x)=xex
x+x2+x32+x46+x524
f(x)=xe−x
f(x)=e−xsinx
x−x2+x33−x530+x690
f(x)=e−xcosx
In Problems 33 and 34, use a Maclaurin series for f to obtain the first four nonzero terms of the Maclaurin expansion for g.
f(x)=1√1−x2;g(x)=sin−1x
x+x36+3x540+5x7112
f(x)=tanx;g(x)=ln(cosx)
In Problems 35–42, use a binomial series to represent each function, and find the interval of convergence.
f(x)=√1+x2
\sum\limits_{k=0}^{\infty}{{1/2}\choose {k}}x^{2k}=1+\dfrac{x^{2}}{2}-\dfrac{x^{4}}{8} +\dfrac{x^{6}}{16}+\ldots; interval: [-1, 1]
f(x)=\frac{1}{\sqrt{1-x}}
f(x)=(1+x)^{1/5}
\sum\limits_{k=0}^{\infty}{{1/5}\choose {k}}x^k=1+\dfrac{x}{5}-\dfrac{2x^{2}}{25} +\dfrac{6x^{3}}{125}+\ldots; interval: [-1, 1]
f(x)=(1-x) ^{5/3}
f(x)=\frac{1}{(1+x^{2}) ^{1/2}}
\sum\limits_{k=0}^{\infty}{{-1/2}\choose {k}}x^{2k}=1-\dfrac{x^{2}}{2}+\dfrac{3x^{4}}{8} -\dfrac{5x^{6}}{16}+\ldots; interval: (-1, 1]
f(x)=\frac{1}{(1+x)^{3/4}}
f(x)= \frac{2x}{\sqrt{1-x}}
\sum\limits_{k=1}^{\infty}2{{-1/2}\choose {k}}(-1)^{k}x^{k+1}=2x+x^{2} +\dfrac{3}{4}x^{3}+\dfrac{5}{8}x^{4}+\ldots; interval: (-1, 1]
f(x)=\frac{x}{1+x ^{3}}
Applications and Extensions
Find the Maclaurin expansion for f(x) =\sin ^{2}x.
Find the Maclaurin expansion for f(x) =\cos ^{2}x.
Obtain the Maclaurin expansion of \cos x by integrating the Maclaurin series for \sin x.
\cos x = \sum\limits_{k=0}^{\infty}{\dfrac{(-1)^{k}x^{2k}}{(2k)!}}
Find the Maclaurin expansion for f(x) =\ln \frac{1}{1-x}. Compare the result to the power series representation of f(x) =\ln \frac{1}{1-x} found in Section 8.8, Example 8, page 607.
Find the first five nonzero terms of the Maclaurin expansion for f(x) =\sec x.
\sec{x}= 1+\dfrac{x^{2}}{2}+\dfrac{5x^{4}}{24}+\dfrac{61x^{6}}{720} +\dfrac{277x^{8}}{8064} + \ldots
Probability The standard normal distribution p(x) = \frac{1}{\sqrt{2\pi}}e^{-x^2\!/2} is important in probability and statistics. If a random variable Z has a standard normal distribution, then the probability that an observation of Z is between Z=a and Z=b is given by P(a\leq Z\leq b) =\frac{1}{\sqrt{2\pi}}\, \int_{a}^{b} e^{-x^2\!/2}\, dx
In Problems 49–52, use a Maclaurin expansion to find each integral.
\int \frac{1}{1+x^{2}}dx
C + \sum\limits_{k=0}^{\infty}{\dfrac{(-1)^{k}x^{2k+1}}{2k+1}}
\int {\sec x}\,dx
\int e^{x^{1/3}}dx
C + \sum\limits_{k=0}^{\infty} {\dfrac{3x^{\frac{k}{3}+1}}{(3+k)k!}}
\int \ln (1+x)\,dx
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Even Functions Show that if f is an even function, then the Maclaurin expansion for f has only even powers of x.
See Student Solutions Manual.
Odd Functions Show that if f is an odd function, then the Maclaurin expansion for f has only odd powers of x.
Show that (1+x)^{m}=\sum\limits_{k\,=\,0}^{\infty } {m\choose k}x^{k}, when m is a nonnegative integer, by showing that R_{n}(x)\rightarrow 0 as n\rightarrow \infty.
See Student Solutions Manual.
Show that the series \sum\limits_{k\,=\,0}^{\infty }{m\choose k}\,x^{k} converges absolutely for \vert x\vert <1 and diverges for \vert x\vert >1 if m<0. (Hint: Use the Ratio Test.)
Show that the interval of convergence of the Maclaurin expansion for f(x) =\sin ^{-1}x is [-1,1].
See Student Solutions Manual.
Euler’s Error Euler believed \frac{1}{2}=1-1+1-1+1-1 +\cdots . He based his argument to support this equation on his belief in the identification of a series and the values of the function from which it was derived.
Challenge Problems
Find the exact sum of the infinite series: \frac{x^{3}}{1(3)}-\frac{x^{5}}{3(5)}+\frac{x^{7}}{5(7)} - \frac{x^{9}}{7(9)}+\cdots \quad \hbox{for } x=1
\dfrac{\pi}{4} - \dfrac{1}{2}
Find an elementary expression for \sum\limits_{k\,=\,1}^{\infty }\frac{x^{k+1}}{k(k+1) }. Hint: Integrate the series for \ln \frac{1}{1-x}.
Show that \sum\limits_{k\,=\,1}^{\infty }\frac{k}{(k+1)!}=1
See Student Solutions Manual.
Let s_{n}=\frac{1}{1!}+\frac{1}{2!}+\cdots \,+\frac{1}{n!},\quad n=1, 2, 3, \ldots \,.
Show that \left[ 1+\frac{1}{n}\right] ^{n}<e for all n>0.
See Student Solutions Manual.
From the fact that \sin t\leq t for all t\geq 0, use integration repeatedly to prove 1-\frac{x^{2}}{2!}\leq \cos x\leq 1-\frac{x^{2}}{2!}+\frac{x^{4}}{4!}\qquad \hbox{for all }x\geq 0
Find the first four nonzero terms of the Maclaurin expansion for f(x) =(1+x) ^{x}.
1+x^{2}-\dfrac{x^{3}}{2}+\dfrac{5x^{4}}{6} + \ldots
Show that f(x) =\left\{ \begin{array}{l@{\quad}l} e^{-1/x^{2}} & x\neq 0 \\ 0 & x=0 \end{array} \right. has a Maclaurin expansion at x=0. Then show that the Maclaurin series does not converge to f.