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Skill Building
In Problems 7–14, use properties of power series to approximate each integral using the first four terms of a Maclaurin series.
\int_{0}^{1}\sin \, x^{2}dx
0.310
\int_{0}^{1}\cos \,x^{2}\,dx
\int_{0}^{1}\dfrac{x^{2}}{1+\cos x}dx
0.195
\int_{0}^{0.1}\dfrac{x}{\ln \,(2+x)}\,dx
629
\int_{0}^{0.2}\sqrt[3]{1+x^{4}}\,dx
0.200
\int_{0}^{1/2}\sqrt[3]{1+x}\,dx
\int_{0}^{1/2}\dfrac{1}{\sqrt[3]{1+x^{2}}}\,dx
0.487
\int_{0}^{0.2}\dfrac{1}{\sqrt{1+x^{3}}}\,dx
Applications and Extensions
Use the recursive formula (7) for \ln (N+1) to show \ln 4\approx 1.38629.
See Student Solutions Manual.
Calculators Are Perfect, Right? They always get the right answer with what looks like little or no effort at all. This is very misleading because calculators use a lot of the ideas learned in this chapter to obtain these answers. One advantage we have over a calculator is that we can approximate answers up to any accuracy we choose. So let’s prove you are smarter than any calculator by approximating each of the following correct to within 0.001 using a Maclaurin series.
Source: Contributed by the students at Lander University, Greenwood, SC.
Leibniz Formula for {\pi} Leibniz derived the following formula for \dfrac{\pi }{4}: \dfrac{\pi}{4}=1-\dfrac{1}{3}+\dfrac{1}{5} -\dfrac{1}{7}+\dfrac{1}{9}-\cdots.
Approximating {\pi} The series approximation of \pi using Gregory’s series converges very slowly. (See Problem 82, Section 8.8. p. 611.) A more rapidly convergent series is obtained by using the identity \tan ^{-1}1=\tan ^{-1} \, \left( \dfrac{1}{2}\right) +\tan ^{-1} \,\left( \dfrac{1}{3}\right)
Use x=\dfrac{1}{2} and x=\dfrac{1}{3} in Gregory’s series, together with this identity, to approximate \pi using the first four terms.
1538665/489888\approx 3.14085
Faster than light? At low speeds, the kinetic energy K, that is, the energy due to the motion of an object of mass m and speed v, is given by the formula K=K(v) =\dfrac{1}{2}mv^{2}. But this formula is only an approximation to the general formula, and works only for speeds much less than the speed of light, c. The general formula, which holds for all speeds, is K_{\text{gen}}(v) =mc^{2} \,\left( \dfrac{1}{\sqrt{1-\dfrac{v^{2}}{c^{2}}}}-1\right)
The formula for K was used very successfully for many years before Einstein arrived at the general formula, so K must be essentially correct for low speeds. Use a binomial expansion to show that \dfrac{1}{2}mv^{2} is a first approximation to K_{\text{gen}} for v close to 0.
Challenge Problems
Let a_{k}=(-1)^{k+1}\int_{0}^{\pi /k}\sin (kx)\,dx.
Find the Maclaurin expansion for f(x) = xe^{x^{3}}.