CLARIFYING THE CONCEPTS
1. Explain what a sample proportion is, using as an example the courses for which you got an A last semester. (p. 415)
7.2.1
If we take a sample of size , the sample proportion is , where represents the number of individuals in the sample that have the particular characteristic. Examples will vary.
2. What is the mean of the sampling distribution of ? (p. 416)
3. Give the formula for the standard error of the proportion. (p. 416)
7.2.3
4. What are the requirements for the sampling distribution of to be approximately normal? (p. 417)
5. Suppose you double the sample size. What happens to the standard error of the proportion? (p. 416)
7.2.5
It decreases by a factor of .
6. For the following values of and , calculate the sample proportion : (p. 415)
PRACTICING THE TECHNIQUES
CHECK IT OUT!
To do | Check out | Topic |
---|---|---|
Exercises 7–18 | Example 12 | Determining whether the CLT for Proportions applies |
Exercises 19–24 | Example 13 | Minimum sample size for approximating normality |
Exercises 25–32 | Example 14 | Finding probabilities using the CLT for Proportions |
Exercises 33–38 | Example 15 | Finding percentiles using the CLT for Proportions |
In Exercises 7–18, samples are taken. Find (a) and (b) , and (c) determine whether the sampling distribution of is approximately normal or unknown.
422
7. ,
7.2.7
(a) 0.5 (b) 0.025 (c) Approximately normal
8. ,
9. ,
7.2.9
(a) 0.05 (b) 0.01541 (c) Approximately normal
10. ,
11. ,
7.2.11
(a) 0.3 (b) 0.1323 (c) Unknown
12. ,
13. ,
7.2.13
(a) 0.002 (b) 0.000999 (c) Unknown
14. ,
15. ,
7.2.15
(a) 0.02 (b) 0.008854 (c) Approximately normal
16. ,
17. ,
7.2.17
(a) 0.01 (b) 0.004450 (c) Approximately normal
18. ,
In Exercises 19–24, find the minimum sample size that produces a sampling distribution of that is approximately normal.
19.
7.2.19
25
20.
21.
7.2.21
50
22.
23.
7.2.23
500
24.
For Exercises 25–32, if possible, find the indicated probability. If it is not possible, explain why not.
25. , ,
7.2.25
0.0668
26. , ,
27. , ,
7.2.27
Not possible since .
28. , ,
29. , ,
7.2.29
0.0531
30. , ,
31. , ,
7.2.31
Not possible since .
32. , ,
For Exercises 33–38, find the indicated value of . If it is not possible, explain why not.
33. , , value of larger than 90% of all values of
7.2.33
0.6628
34. , , value of larger than 10% of all values of
35. , , 95th percentile of values of
7.2.35
Not possible since .
36. , , 5th percentile of values of
37. , , 2.5th percentile of values of
7.2.37
0.1477
38. , , 97.5th percentile of values of
APPLYING THE CONCEPTS
39. Abandoning Landlines. The National Health Interview Survey reports that 25% of telephone users no longer use landlines, and have switched completely to cell phone use. Suppose we take samples of size 36.
7.2.39
(a) (b) Approximately normal (0.25, 0.0722) (c) 0.4443 (TI-83/84: 0.4449)
40. LeBron James. During the 2013-2014 National Basketball Association season, 75% of LeBron James's free throws were successful. Suppose we take a sample of 50 of LeBron's free throws.
41. Small Business Jobs. According to the U.S. Small Business Administration, small businesses provide 75% of the new jobs added to the economy. Suppose we take samples of 20 new jobs.
7.2.41
(a) (b) 0.7324 (TI-83/84: 0.7323) (c) 0.0959 (TI-83/84: 0.0954)
42. Facebook Accounts. In 2014, the Harvard University Institute of Politics surveyed 3058 people 18 to 29 years old and found 2569 who had a Facebook account.7 Suppose we take samples of 256 18- to 29-year-olds.
43. Abandoning Landlines. Refer to Exercise 39.
7.2.43
(a) 0.1312, 0.3688
(b)
(c) For . Thus is considered moderately unusual. (d) Sample proportions between 0 and 0.0334 inclusive and between 0.4666 and 1 inclusive would be considered outliers.
44. LeBron James. Refer to Exercise 40.
45. Small Business Jobs. Refer to Exercise 41.
423
7.2.45
(a) 0.5003, 0.9997 (TI-83/84: 0.5007, 0.9993)
(b)
(c) For . Thus is neither moderately unusual nor an outlier.
46. Facebook Accounts. Refer to Exercise 42.
47. Facebook Accounts. Refer to Exercises 42 and 46. What if we increased the sample size to some unspecified larger number? Describe how and why the following quantities would change, if at all:
7.2.47
(a) Remains the same since does not depend on .
(b) Decrease. Since the sample size is in the denominator of decreases as the sample size increases. (c) Decrease. Standardizing we get . From (b), decreases as the sample size increases. Therefore increases as the sample size increases. Therefore decreases.
(d) Increase. Standardizing we get and . From (b), decreases as the sample size increases. Therefore decreases and increases as the sample size increases. Thus increases as the sample size increases. (e) Decrease. Standardizing we get . From (b), decreases as the sample size increases. Therefore decreases as the sample size increases. Thus decreases as the sample size increases. (f) Increase. The 2.5th percentile is found by the formula . From (a) remains the same as the sample size increases and from (b) decreases as the sample size increases. Therefore increases as the sample size increases. (g) Decrease. The 97.5th percentile is found by the formula . From (a) remains the same as the sample size increases and from (b), decreases as the sample size increases. Therefore decreases as the sample size increases.
BRINGING IT ALL TOGETHER
Partners Checking Up on Each Other. Use the following information for Exercises 48–51. According to a study in the journal Computers in Human Behavior,8 65% of the college women surveyed checked the call histories on the cell phones of their partners, whereas 41% of the males did so.
48. Suppose we take a sample of 100 college females and 100 college males.
49. Refer to Exercise 48. Calculate the following probabilities:
7.2.49
(a) 0.5 (b) 0 (c) 0 (d) 0.5
50. Refer to Exercise 48.
51. Suppose someone claimed that there really was no difference in the proportions of females and males who check the call histories on their partners' cell phones. How would you use the results from Exercises 49 and 50 to address this claim?
7.2.51
The results of Exercises 49 and 50 do not support this claim. The 97.5th percentile for the males is less than the 2.5th percentile for the females. Also and are both very different for males and females.