Find symmetric equations of the normal line to the hyperboloid of one sheet defined by the equation x2+y2−z2=24 at the point (3,−4,1).
Solution The surface is given by F(x,y,z)=x2+y2−z2−24=0. From Example 1, {\boldsymbol \nabla } F( 3,-4,1) =6\mathbf{i}-8\mathbf{j}-2\mathbf{k}. Since the normal line is in the direction of the gradient, symmetric equations of the normal line to the hyperboloid at (3,-4,1) are \frac{x-3}{6}=\frac{y+4}{-8}=\frac{z-1}{-2}