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Concepts and Vocabulary
True or False If F is differentiable at a point P0=(x0,y0,z0) on the surface F(x,y,z)=0, and if {\bf \boldsymbol \nabla }F(x_{0},y_{0},z_{0})\neq \mathbf{0}, then the surface has a tangent plane at P_{0}.
True
True or False The normal line to the surface F(x,y,z)=0 at a point P_{0}=(x_{0},y_{0},z_{0}) is in the direction of the gradient {\boldsymbol \nabla }F(x_{0},y_{0},z_{0}), provided {\boldsymbol \nabla }F(x_{0},y_{0},z_{0})\neq \mathbf{0}.
True
Skill Building
In Problems 3–6, find an equation of the tangent plane to each surface at the given point.
z=10-2x^{2}-y^{2} at ( 0,2,6)
4y+z = 14
z=4+x^{2}+y^{2} at ( 1,-2,9)
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z=4x^{2}+9y^{2} at ( 1,1,13)
8x + 18y - z = 13
z=\sqrt{x^{2}+3y^{2}} at ( 1,1,2)
In Problems 7–18:
x^{2}+y^{2}+z^{2}=14 at (1,-2,3)
2x^{2}+3y^{2}+z^{2}=12 at (2,1,-1)
4x^{2}+y^{2}-2z^{2}=3 at (1,1,-1)
z^{2}=x^{2}+3y^{2} at (1,-1,-2)
z=x^{2}+y^{2} at (-2,1,5)
z=2x^{2}-3y^{2} at (2,1,5)
2x^{2}-y^{2}=z at (1,0,2)
x^{2}+y^{2}-2z^{2}=-13 at (2,1,3)
x^{2}-3y^{2}-4z^{2}=2 at (3,1,1)
x^{2}+2y^{2}-5z^{2}=4 at (1,2,1)
f(x,y)=\ln ( \sec (x^{2}+y^{2})) at \left( \sqrt{\dfrac{\pi }{8}},\sqrt{\dfrac{\pi }{8}},\ln \sqrt{2}\right)
f(x,y)=\dfrac{x^{2}-y^{2}}{x^{2}+y^{2}} at \left(1,2, -\dfrac{3}{5}\right)
In Problems 19–22:
z=e^{x}\cos y at \left( 0,\dfrac{\pi}{2},0\right)
z=\ln (x^{2}+y^{2}) at (1,-1,\ln 2)
x^{2/3}+y^{2/3}+z^{2/3}=9 at (1,8,-8)
x^{1/2}+y^{1/2}+z^{1/2}=6 at (1,4,9)
Applications and Extensions
Show that the same results would have been obtained in Example 1 by solving the equation x^{2}+y^{2}-z^{2}-24=0 for z and using the function z=f(x,y)=\sqrt{x^{2}+y^{2}-24} whose graph is the part of the hyperboloid lying above the xy-plane.
See Student Solutions Manual.
Show that the same results would have been obtained in Example 2 by solving the equation x^{2}+y^{2}-z^{2}-24=0 for z and using the function z=f(x,y)=\sqrt{x^{2}+y^{2}-24} whose graph is the part of the hyperboloid lying above the xy-plane.
In Problems 25–30, determine the point(s) on the surface of z=f( x,y) at which the tangent plane is parallel to the xy-plane.
z=6x-4y-x^{2}-2y^{2}
The tangent plane is parallel to the xy-plane at (x, y, z) = ( 3, -1, 11 ).
z=4x-2y+x^{2}+y^{2}
z=x^{2}+2xy+y^{2}
The tangent plane is parallel to the xy-plane for all (x, y, z) such that y =-x and z = 0.
z=x^{2}-3xy+y^{2}
z=2x^{4}-y^{2}-x^{2}-2y
The tangent plane is parallel to the xy-plane at (x, y, z) = (0, -1, 1 ), \left(\dfrac{1}{2}, -1,\dfrac{7}{8}\right), and \left(-\dfrac{1}{2},-1,\dfrac{7}{8}\right).
z=x^{2}+y^{4}-4y^{2}-2x
Solar Panel An engineer is building experimental, dome- shaped living quarters 4\,\rm{m} high and modeled by the function z=4-x^{2}-y^{2}. She wants to bolt a flat solar panel to the dome at the point (1,1,2). In what direction should the engineer drill?
The engineer should drill in the direction .
Normal Lines of a Sphere Show that the normal lines of a sphere x^{2}+y^{2}+z^{2}=R^{2} pass through the center of the sphere.
See Student Solutions Manual.
Normal Line of a Sphere Let P_{0}=(x_{0},y_{0},z_{0}) be a point on the sphere x^{2}+y^{2}+z^{2}=R^{2}. Show that the normal line to the sphere at P_{0} passes through the point (-x_{0},-y_{0},-z_{0}).
Tangent Plane Find equations of the tangent plane and normal line to \sin (x+y)+\sin (y+z)=1 at the point \left( 0,\dfrac{\pi }{ 2},\dfrac{\pi }{2}\right) .
The equation of the tangent plane is y+z=\pi. The symmetric equations for the normal are {{y - {\pi \over 2}} \over { - 1}} = {{z - {\pi \over 2}} \over { - 1}},\;x = 0.
Tangent Plane to an Ellipsoid Find the points on the surface \dfrac{x^{2}}{9}+\dfrac{y^{2}}{4}+\dfrac{z^{2}}{36}=1, where the tangent plane is parallel to the plane 2x-3y+z=4.
Tangent Plane to a Cylinder Show that the tangent plane to the cylinder x^{2}+y^{2}=a^{2} at the point (x_{0},y_{0},z_{0}) is given by the equation x_{0}x+y_{0}y=a^{2}.
See Student Solutions Manual.
Tangent Plane to a Cone Show that the tangent plane to the cone \dfrac{z^{2}}{c^{2}}=\dfrac{x^{2}}{a^{2}}+\dfrac{y^{2}}{b^{2}} at the point (x_{0},y_{0},z_{0})\neq (0,0,0) is given by the equation \dfrac{ z_{0}}{c^{2}}z=\dfrac{x_{0}}{a^{2}}x+\dfrac{y_{0}}{b^{2}}y. Why must the point of tangency be different from the origin?
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Show that at any point, the sum of the intercepts on the coordinate axes of the tangent plane to the surface x^{1/2}+y^{1/2}+z^{1/2}=a^{1/2}, a>0, is a constant.
See Student Solutions Manual.
Challenge Problems
Tangent Line Find an equation of the tangent line to the curve of intersection of the surfaces x\sin (yz) =1 and ze^{y^{2}-x^{2}}=\dfrac{\pi }{2} at the point \left( 1,1,\dfrac{\pi }{2} \right) .
Find equations of the tangent plane and normal line to (yz)^{xz}=16 at the point (2,1,2).
An equation of the tangent plane is (\ln 2) x + 2 y + (1 + \ln 2) z = 4 (1+ \ln 2). Symmetric equations of the normal line are {{x - 2} \over {\ln 2}} = {{y - 1} \over 2} = {{z - 2} \over {1 + \ln 2}}.
Consider the tangent plane to the graph of a differentiable function z=f(x,y) at a point (x_{0},y_{0}). Suppose \mathbf{v}_{1} is a tangent vector on the plane whose \mathbf{j} component is 0 and \mathbf{v}_{2} is a tangent vector on the plane whose \mathbf{i} component is 0. Must \mathbf{ v}_{1} and \mathbf{v}_{2} be at right angles? See the figure.