CLARIFYING THE CONCEPTS
1. For a continuous random variable , why are we not interested in whether equals some particular value? (p. 349)
6.4.1
The probability that X equals some particular value is zero.
2. In the graph of a probability distribution, what is represented on the number line? (p. 349)
3. How is probability represented in the graph of a continuous probability distribution? (p. 350)
6.4.3
Area under the normal distribution curve above an interval.
4. What are the possible values for the mean of a normal distribution? For the standard deviation? (p. 352)
5. True or false: The graph of the uniform distribution is always shaped like a square. (p. 350)
6.4.5
False
6. For continuous probability distributions, what is the difference between and ? (p. 351)
7. What is the value for the mean of the standard normal distribution? (p. 354)
6.4.7
0
8. What is the value for the standard deviation of the standard normal distribution? (p. 354)
9. True or false: The area under the curve to the right of is 0.5. (p. 354)
6.4.9
True
10. True or false: . (p. 349)
PRACTICING THE TECHNIQUES
CHECK IT OUT!
To do | Check out | Topic |
---|---|---|
Exercises 11–20 |
Example 25 | Uniform probability distribution |
Exercises 21–30 |
Example 26 | Normal distribution mean and standard deviation |
Exercises 31–36 |
Example 27 | Properties of the normal curve |
Exercises 37–44 |
Example 28 | Find the area to left of the -value |
Exercises 45–48 |
Example 29 | Find the area to right of the -value |
Exercises 49–58 |
Example 30 | Find the area between two -value |
Exercises 59–70 |
Example 32 | Expressing areas under the standard normal curve as probabilities |
Exercises 71–78 |
Example 33 | Finding the -value, given area to its left |
Exercises 79–86 |
Example 34 | Finding the -value, given area to its right |
Exercises 87–90 |
Example 35 | Find two that mark the boundaries of the middle 95% of the area |
For Exercises 11–16, assume that is a uniform random variable, with left endpoint 0 and right endpoint 100. Find the following probabilities:
11.
6.4.11
0.5
12.
13.
6.4.13
0.65
14.
15.
6.4.15
0.01
16.
364
For Exercises 17–20, assume that is a uniform random variable, with left endpoint −5 and right endpoint 5. Compute the following probabilities:
17.
6.4.17
0.5
18.
19.
6.4.19
0.1
20.
21. The two normal distributions in the accompanying figure have the same standard deviation of 5 but different means. Which normal distribution has mean 10 and which has mean 25? Explain how you know this.
6.4.21
A has mean 10; B has mean 25. The peak of a normal curve is at the mean; from the graphs we see that the mean of A is less than the mean of B.
22. The two normal distributions in the figure below have the same mean of 100 but different standard deviations. Which normal distribution has standard deviation 3 and which has standard deviation 6? Explain how you know this.
For Exercises 23–30, use the graph of the normal distribution to determine the mean and standard deviation. (Hint: The distance between dotted lines in the figures represents 1 standard deviation.)
23.
6.4.23
,
24.
25.
6.4.25
,
26.
27.
6.4.27
,
28.
29.
6.4.29
,
30.
Use the normal distribution from Example 27 for Exercises 31–36. Birth weights are normally distributed with a mean weight of and a standard deviation of .
31. What is the probability of a birth weight equal to 3285 grams?
6.4.31
0
32. What is the probability of a birth weight more than 3285 grams?
33. What is the probability of a birth weight of at least 3285 grams?
6.4.33
0.5
34. What can we say about the area to the left of 3285 grams and the area to the right of 3285 grams?
35. Is the area to the right of greater than or less than 0.5? How do you know this?
6.4.35
Less than 0.5. Since is greater than the mean of 3285 and the area to the right of is 0.5, the area to the right of is less than the area to the right of .
36. Is the area to the left of greater than or less than 0.5? How do you know this?
365
For Exercises 37–58,
Find the area under the standard normal curve that lies to the left of the following:
37.
6.4.37
(a)
(b) 0.8143
38.
39.
6.4.39
(a)
(b) 0.9987
40.
41.
6.4.41
(a)
(b) 0.0035
42.
43.
6.4.43
(a)
(b) 0.4207
44.
Find the area under the standard normal curve that lies to the right of the following:
45.
6.4.45
(a)
(b) 0.1020
46.
47.
6.4.47
(a)
(b) 0.9987
48.
Find the area under the standard normal curve that lies between the following:
49. and
6.4.49
(a)
(b) 0.3413
50. and
51. and
6.4.51
(a)
(b) 0.0214
52. and
53. and
6.4.53
(a)
(b) 0.3413
54. and
55. and
6.4.55
(a)
(b) 0.0214
56. and
57. and
6.4.57
(a)
(b) 0.7994
58. and
For Exercises 59–70, find the indicated probability for the standard normal .
59.
6.4.59
(a)
(b) 0
60.
61.
6.4.61
(a)
(b) 1
62.
63.
6.4.63
(a)
(b) 0.0150
64.
65.
6.4.65
(a)
(b) 0.9500
66.
67.
6.4.67
(a)
(b) 0.1725
68.
69.
6.4.69
(a)
(b) 0.5000
70.
For Exercises 71–78, find the -value with the following areas under the standard normal curve to its left. Draw the graph, and then find the -value.
71. 0.3336
6.4.71
72. 0.4602
73. 0.3264
6.4.73
74. 0.4247
75. 0.95
6.4.75
1.65 (TI-83/84: 1.645)
76. 0.975
77. 0.98
6.4.77
2.05
78. 0.99
For Exercises 79–86, find the -value with the following areas under the standard normal curve to its right. Draw the graph, and then find the -value.
79. 0.8078
6.4.79
80. 0.3085
81. 0.9788
6.4.81
82. 0.5120
83. 0.90
6.4.83
𢄒1.28>
84. 0.975
85. 0.9988
6.4.85
−3.036 (Using the table, both −3.03 and −3.04 have area to the left of them equal to 0.0012 and area to the right of them as 0.9988.)
86. 0.9998
For Exercises 87–94, find the values of that mark the boundaries of the indicated areas.
87. The middle 80%
6.4.87
−1.28 and 1.28
88. The middle 95%
89. The middle 98%
6.4.89
−2.33 and 2.33
90. The middle 85%
91. Find the 50th percentile of the distribution. (Hint: See margin note on page 360.)
6.4.91
92. Find the 75th percentile of the distribution.
93. Find the value of that is larger than 99.5% of all values of .
6.4.93
94. Find the value of that is smaller than 99.5% of all values of .
APPLYING THE CONCEPTS
95. Uniform Distribution: Web Page Loading Time.
Suppose that the Web page loading time for a particular home network is uniform, with left endpoint 1 second and right endpoint 5 seconds.
6.4.95
(a) 0.25 (b) 0.25 (c) 0 (d) 0. Area underneath the curve for a single value of is the area of a line that is 0.
96. Uniform Distribution: Random Number Generation.
Computers and calculators use the uniform distribution to generate random numbers. Suppose we have a calculator that randomly generates numbers between 0 and 1, so that they form a uniform distribution.
What is the probability that a random number greater than 1 is generated?
366
For Exercises 97–100, sketch the distribution, showing , and .
97. Windy Frisco. The average wind speed in San Francisco in July is 13.6 miles per hour (mph), according to the U.S. National Oceanic and Atmospheric Administration. Suppose that the distribution of the wind speed in July in San Francisco is normal, with mean mph and standard deviation .
6.4.97
98. Price of Crude Oil. The Organization of Petroleum Exporting States reports that the mean price for crude oil in July 2014 was $105.115 (one hundred five dollars, eleven and a half cents) per barrel. Assume the data is normal, with mean and standard deviation .
99. Hospital Patient Length of Stays. A study of Pennsylvania hospitals showed that the mean patient length of stay was 4.87 days, with a standard deviation of 0.97 day.16 Assume that the distribution of patient length of stays is normal.
6.4.99
100. Facebook Friends. Statistica reported in 2014 that the mean number of Facebook friends for 18- to 24-year-olds was 649. Assume the distribution is normal, with friends and standard deviation friends.
101. Percentiles of the Uniform Distribution. The th percentile of a continuous distribution is the value of that is greater than or equal to % of the values of . Find the following percentiles of the uniform distribution in Example 25:
6.4.101
(a) 9.5 minutes (b) 9 minutes (c) 9.75 minutes (d) 0.5 minute (e) 1 minute (f) 0.25 minute
102. Mean of the Uniform Distribution. Explain two ways that you could find the mean of the uniform distribution.
For Exercises 103–114, use the graph of the standard normal distribution to find the shaded area using the table or technology.
103.
6.4.103
0.9750
104.
105.
6.4.105
0.4821
106.
107.
6.4.107
0.0179
108.
109.
6.4.109
0.8020
110.
111.
6.4.111
0.1832
367
112.
113.
6.4.113
0.9641
114.
115. Standardized Test Scores. Nicholas took a standardized test and was informed that the -value of his test score was 1.0. Find the percentages of test takers that Nicholas scored higher than.
6.4.115
0.8413
116. Standardized Test Scores. Samantha's -value for her standardized test performance was 1.5. Calculate the proportion of test takers that Samantha scored higher than.
117. High Jump. Brandon's score in the high jump at a track-and-field event showed that he was able to jump higher than 45% of the competitors. Find the -value for Brandon's high-jump score.
6.4.117
−0.13
118. Body Temperature. The body temperatures of all the students in Kayla's class were measured. Kayla's body temperature was lower than 90% of her classmates. Find the -value corresponding to Kayla's body temperature.
119. Checking the Empirical Rule. Check the accuracy of the Empirical Rule for . That is, find the area between and using the techniques of this section. Then compare your finding with the results for using the Empirical Rule.
6.4.119
The area between and is 0.9544. By the Empirical Rule, the area between and is about 0.95.
120. Checking the Empirical Rule. Check the accuracy of the Empirical Rule for . That is, find the area between and using the techniques of this section. Then compare your finding with the results for using the Empirical Rule.
121. Without Tables or Technology. Find the following areas without using the table or technology. The area to the left of is 0.0668.
6.4.121
(a) 0.0668 (b) 0.9332 (c) 0.8664
122. Without Tables or Technology. Find the following areas without using the table or technology. The area to the right of is 0.0035.
123. Values of That Mark the Middle 99%. Find the two values of that contain the middle 99% of the area under the standard normal curve.
6.4.123
and .
124. Values of That Mark the Middle 90%. Find the two values of that contain the middle 90% of the area under the standard normal curve.
Use the Normal Density Curve applet for Exercise 125.
125. Find the quartiles of the standard normal distribution. That is, find the 25th, 50th, and 75th percentiles of the standard normal distribution.
6.4.125
−0.67; 0; 0.67
BRINGING IT ALL TOGETHER
Chapter 6 Case Study: SAT Scores and AP Exam Scores
The College Board reports that the population mean Critical Reading SAT score in 2013 was = 496, with a population standard deviation of , and that the scores followed a normal distribution. Use this information for Exercises 126–131.
126. Draw the graph of this distribution. Mark the number line with the increments of and .
127. Suppose a different exam had the following parameter values: and . Explain how the distribution graph would be similar and how it would be different from the graph in Exercise 126.
6.4.127
The peak would still be at but since the standard deviation is larger the curve would be flatter and more spread out.
128. Suppose a different exam had the following parameter values: and . Explain how the distribution graph would be similar and would be different from the graph in Exercise 126.
129. What can we say about and ? What property of the normal distribution allows us to say this?
6.4.129
They are both equal to 0.5. The property that the mean equals the median.
130. Which of the following probabilities is larger: or ? How do you know this?
131. Confirm your work from Exercise 130 as follows: The -value associated with is , and the -value associated with is . Find and . Does this confirm your work from Exercise 130?
6.4.131
and ; yes